Phương trình chuỗi - Hóa 9

docx 3 trang mainguyen 5120
Bạn đang xem tài liệu "Phương trình chuỗi - Hóa 9", để tải tài liệu gốc về máy bạn click vào nút DOWNLOAD ở trên

Tài liệu đính kèm:

  • docxphuong_trinh_chuoi_hoa_9.docx

Nội dung text: Phương trình chuỗi - Hóa 9

  1. Cõu 1: (2 điểm ) Hoàn thành chuỗi biến húa sau: (1) (2) (3) (4) Fe FeCl3 Fe(OH)3 Fe2O3 Fe2(SO4)3 t0 (1) 2 Fe + 3 Cl2 2 FeCl3 (2) FeCl3 +3KOH → Fe(OH)3 ↓+ 3 KCl t0 (3) 2 Fe(OH)3 Fe2O3 + 3 H2O (4) Fe2O3 + 3 H2SO4 → Fe2(SO4)3 + 3 H2O Al(OH)3 (1) Al2O3 (2) Al 0 (3) t   Al2O3 + 3H2O 2Al(OH)3 Al2(SO4)3 (4) AlCl3. dpnc 2Al2O3 criolit 4Al + 3O2 2Al + 3H2SO4  Al2(SO4)3 + 3H2 Al2(SO4)3 + 3BaCl2  3BaSO4 + 2AlCl3 3/ Al AlCl3 Al (OH)3 Al2O3 Al(NO3)3 Al t 0 2Al + 3Cl2  2AlCl3 AlCl3 + 3NaOH Al(OH)3 + 3NaCl t 0 2Al(OH)3  Al2O3 + 3H2O Al2O3 + 6HNO3 2Al(NO3)3 + 3H2O 2Al(NO3)3 + 3Mg 3Mg(NO3)2 + 2Al (1) (2) (3) (4) 4/ Fe  FeCl3  Fe(OH)3  Fe2O3  Fe2(SO4)3 t0 1) 2Fe + 3Cl2  2FeCl3 2) FeCl3 + 3NaOH Fe(OH) 3  +3 NaCl t0 3) 2Fe(OH)3  Fe2O3 + 3H2O 4) Fe2O3+ 3H2SO4 Fe 2(SO4)3 + 3H2O 5/ CuO CuCl2 Cu(OH)2 CuO CuSO4 Cu(NO3)2 Cu 1. CuO + 2HCl CuCl2 + H2O 2. CuCl2 + 2NaOH Cu(OH)2 + 2NaCl 3. Cu(OH)2 CuO + H2O
  2. 4. CuO + H2SO4 CuSO4 + H2O 5. CuSO4 + Ba(NO3)2 Cu(NO3)2 + BaSO4 6. Fe + Cu(NO3)2 Fe(NO3)2 + Cu (1) (2) (3) (4) 6// Al Al2(SO4)3 Al(OH)3 Al2O3 Al (1). 2 Al + 3 H2SO4 Al2(SO4)3 + 3 H2 (2). Al2(SO4)3 + 6 NaOH 2 Al(OH)3 + 3 Na2SO4 0 (3). 2 Al(OH)3 t Al2O3 + 3 H2O Đpnc; Criolit (4). 2 Al2O3 4 Al + 3 O2 7// (1) FeCl2 (2) Fe(OH)2 (3) FeO Fe (4) FeCl3 (5) Fe(NO3)3 (6) Fe 1. Fer + 2HCldd FeCl2 dd + H2 k ( 0.5ủ) 2. FeCl2 dd + 2NaOhdd Fe(OH)2 r + 2NaCldd ( 0.5ủ) 3. Fe(OH)2 r FeOr + H2O l ( 0.5ủ) 4. 2Fer + 3Cl2 k 2FeCl3 r ( 0.5ủ) 5. FeCl3 dd + 3AgNO3 dd Fe(NO3)3 dd + 3AgClr ( 0.5ủ) 6. 2Fe(NO3)3 dd + 3Znr 3Zn(NO3)2 dd + 2Fer 8// Cu → CuO → CuSO 4 → CuCl2 → Cu(OH)2 t0 2Cu + O2  2CuO CuO + H2SO4 CuSO4 + H2O CuSO4 + BaCl2 CuCl2 + BaSO4  CuCl2 + 2NaOH Cu(OH)2  + 2NaCl 0 0 +O2 ;t +HCl +NaOH t 9//Cu đ CuO đ CuCl2 đ Cu( OH )2 đ CuO ( 1 ) ( 2 ) ( 3 ) ( 4 ) t0 2Cu +O 2CuO 1) 2 đ 2) CuO +2HCl đ CuCl2 +H2O 3) CuCl2 +2NaOH đ Cu( OH )2 ¯ +2NaCl t0 Cu( OH ) CuO +H O 4) 2 đ 2
  3. Cõu 10: 1 2 3 4 5 C  CO  CO2  Ca(HCO3)2  CaCO3  CaCl2 6  NaHCO3 t0 (1) C + CO2  2CO t0 (2) 2CO + O2  2CO2 (3) CaCO3 + CO2 + H2O  Ca(HCO3)2 t0 (4) Ca(HCO3)2  CaCO3 + CO2 + H2O (5) CaCO3 + 2HCl  CaCl2 + H2O + CO2 (6) CO2 + NaOH  NaHCO3 Cõu 11: 1 2 3 4 5 MnO2  Cl2  FeCl3  NaCl  Cl2  HCl 6 HClO t0 (1)4HCl(đặc) + MnO2  MnCl2 + Cl2 + 2H2O KClO3 + 6HCl (đ)  KCl + 3Cl2 + 3H2O t0 (2) 2Fe + 3Cl2  2FeCl3 (3) FeCl3 + 3NaOH  Fe(OH)3 + 3NaCl ĐPCMN (4) NaCl + H2O  NaOH + Cl2 + H2 (5) Cl2 + H2 AS 2HCl (6) Cl2 + H2O  HCl + HClO Cõu 12: 1 2 3 4 5 CO  CO2  Na2CO3  NaHCO3  Na2CO3  NaOH 6  CO2 t0 (1) 2CO + O2  2CO2 (2) CO2 + NaOH  Na2CO3 + H2O t0 (3) Na2CO3 + H2O + CO2  2NaHCO3 (4) NaHCO3  Na2CO3 + H2O + CO2 (5) Na2CO3 + Ca(OH)2  CaCO3 + 2NaOH (6) NaHCO3 + HCl  NaCl + H2O + CO2